(3x-1)-(x+6)=-5/(1-3x)^2

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Solution for (3x-1)-(x+6)=-5/(1-3x)^2 equation: 



(3x-1)-(x+6)=-5/(1-3x)^2

We move all terms to the left:

(3x-1)-(x+6)-(-5/(1-3x)^2)=0



Domain of the equation: (1-3x)^2)!=0

We move all terms containing x to the left, all other terms to the right

-3x)^2!=-1

x!=-1/1

x!=-1

x∈R



We add all the numbers together, and all the variables

(3x-1)-(x+6)-(-5/(-3x+1)^2)=0

We get rid of parentheses

3x-x-(-5/(-3x+1)^2)-1-6=0

We multiply all the terms by the denominator


3x*(-3x+1)^2)-x*(-3x-3x+1)^2)-6*(-3x+1)^2)+1)^2)-(-5-1*(=0

We add all the numbers together, and all the variables

3x*(-3x+1)^2)-x*(-6x+1)^2)-6*(-3x+1)^2)+1)^2)-(-5-1*(=0

We add all the numbers together, and all the variables

-6x+3x*(-3x+1)^2)-x*(+1)^2)-6*(-3x+1)^2)+1)^2)-(-5-1*(=0

We add all the numbers together, and all the variables

-6x+3x*(-3x+1)^2)-x*1^2)-6*(-3x+1)^2)+1)^2)-(-5-1*(=0

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